Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
Answer:
The correct answer will be option- Clinical examination
Explanation:
Clinical examination is performed by the medical practitioner in which the practitioner examines the patient for a medical condition based on the physical condition of the patient.
The examination involves the three steps: a history of the patient, examination of the symptoms based on the medical reports and the possible explanation of for the cause.
Since in the given question, the dietician after noticing the physical health assessed the nutrition therefore the doctor is performing the clinical examination.
Answer:
D
Explanation:
<em>They</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>used</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>bod</em><em>y</em><em> </em><em>on</em><em> </em><em>daily</em><em> </em><em>basis</em><em> </em><em> </em><em>bec</em><em>ause</em><em> </em><em>they</em><em> </em><em>ha</em><em>ve</em><em> </em><em>less</em><em> </em><em>nutrie</em><em>nts</em>
I) Locus- the chromosomal site where a specific gene is located. A locus is a fixed position on a chromosome, like the position of a gene or a marker. Each chromosome carries ,many genes; human's estimated haploid (n) protein coding genes are about 20,000, on the 23 different chromosomes.
ii) Interference; the observed double crossover frequency differs from the expected double crossover frequency. Cross over interference is used to refer to the non-random placement of crossovers with respect to each other during meiosis. It results in widely spaced crossovers along chromosomes. Interference may exert its effect across whole chromosomes. As chromosomes in many eukaryotes are large, interference must be able to act over megabase lengths of DNA.
iii) Linkage- the tendency for genes located in close proximity on the same chromosome to be inherited together. Normally when two genes are close together on the same chromosome, they do not assort independently and are said to be linked. Whereas genes located on different chromosomes assort independently and have a recombination frequency of 50%, linked genes have a recombination frequency that is less than 50%.
iv) Recombination- the process by which a new pattern of alleles on a chromosome is generated. Genetic recombination is the production of offspring with combinations f traits that differ from those found in either parent. During meiosis in eukaryotes, genetic recombination involves the pairing of homologous chromosomes. This may be followed by information transfer between the chromosomes.
Differentiation is the process that involves the turning off or on the genetic information of a cell.
Differentiation is the process in which a young and immature cell changes into a specialized cell (a mature form with distinct function). Generic embryonic cells undergo differentiation to become specialized cells through the process of gene expression in which specific combination of genetic instructions are turned on (expressed) or off (repressed).
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