Answer:
The population is not following the Hardy-Weinberg equilibrium.
Explanation:
Hardy-Weinberg proposed that the population will remain in the equilibrium if they are not affected with the external natural force like genetic drift, mutation and many others. The gene pool of a population will remain in equilibrium state for generations.
The mathematical expression for the Hardy-Weinberg are
Genotypic frequency is p²+q²+2pq=1
Allele frequency is p+q=1
where p-dominant allele,
q-recessive allele
Therefore,calculating expected frequency of allele q,
q² (recessive genotype)- q²+2pq/1000
= 22+188/1000
=210/1000
= 0.21
q= 0.45
Calculating expected frequency of allele p,
Using p+q=1
p=1-q
p= 0.55 (expected)
Calculating observed value of frequency of p,
p²= p²+2pq/1000
= 790+188/1000
= 978/1000
= 0.978
p = 0.988 (observed)
Since the expected frequency does not match the observed frequency therefore the population is not under the Hardy-Weinberg equilibrium and the gene pool is disturbed.
Answer:
They have a variety of traits to study.
Explanation:
The other options are irrelevant to the study of inherited traits.
The answer is Protist. Oganisms
in this group are referred to as unicellular
"animal-like" protozoa. They are later classified into ciliated, flagellated, phagocytic, and spore-forming.
This group is reserved for microscopic
organisms while Protoctista groups multicellular
eukaryote organisms such as slime molds.
Yellow jackets and miner bees are the only types I found hope it helps
