Answer:
First part representing requirements for the length x>=5 ft
Second part yes
Step-by-step explanation:
Well, the formula for finding the area of a rectangle is l x w. In the question, it states that the pen must be 4 ft wide and to fit his requirements of the pen being at the minimum 20 ft^2 we have this inequality 4x>=20 which we must solve and we get x>=5 which means that this represents all of the possible lengths for the play space. For the second part, we know that to fufill Judah's requirements for square ft., our length must be greater than or equal to 5. Last time I was doing math, I'm pretty sure 5 1/2>5 which thus can be accepted as a length value, still meeting the requirements of at least 20ft^2 space for the play space.
This is in its simplest form.
Decimal form is 1.375
Answer:
y=3/2x - 5
Step-by-step explanation:
Subtract the 2y to move it to the other side
Subtract the 3x to move it to the other side
you get the equation of -2y=-3x + 10
Divide by -2
Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
The area of the shaded region will be the area of the rectangle minus the area of the white square inside of it:
((x+10)(2x+5)) - ((x+1)(x+1))
First, FOIL both of the areas separately:
(2x^2 + 5x + 20x + 50) - (x^2 + x + x + 1)
Simplify within the parentheses by adding like terms:
(2x^2 + 25x + 50) - (x^2 + 2x + 1)
Now, subtract one equation from the other:
2x^2 + 25x + 50
-x^2 - 2x - 1
= x^2 + 23x + 49
This will be the equation for the area.
