Is this argument VALID or INVALID?
2 answers:
You might be interested in
So to find the answer you have to know what the mixture is, what the trend is,
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
