Answer:
the genotype of the parent guinea pigs are as follows:
RrBb (rough, black) and Rrbb (rough, white)
Explanation:
Since the phenotype of smooth coat is present in the offspring, the parent genotype cannot have RR alleles for their coat. Similarly, the rough, black parent cannot have BB alleles in its genotype because that will not yield a white coat color in its offspring.
After making the dihybdrid cross, the probability obtained for each phenotype is given below:
rough black: 
rough white:
smooth black: 
smooth white:
Hope that answers the question, have a great day!
This movement is called diffusion
Answer:
There are 2 answers:
1/The number of producers is greater than the number of primary consumers.
2/The amount of energy at the primary consumer level is greater than the amount of energy at the secondary consumer level.
Explanation:
Answer:
3/16
Explanation:
Assuming that green, smooth peas are the dominant trait, as long as the gene has a dominant allele for colour or texture of the peas, the peas will be green or smooth respectively.
Hence wrinkled and yellow are the recessive traits. That must have a combination of 2 recessive alleles in the gene to have the recessive trait.
Assuming G is the allele for green and g is the allele coding for yellow peas, and W represents allele for smooth skin and w represents wrinkled skin,
The probability of 2 heterozygote parents (green and smooth) crossing with genotype of GgWw and GgWw to get offspring with Green and wrinkled peas of genotype G_ww (whereby _ represents either G or g), is 3/16 refer to diagram above.
they are heterotrophs, as they can not make or synthesize their own food.
