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natka813 [3]
3 years ago
15

What is the GFC of 21, 35, and 49?

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0
The greatest common factor of 21, 35, and 49 is: 7

Since 21 is the lowest number we are solving up to, so no other factors can be given after that.
Factors of 21: 1, 3, 7, 21
Factors of 35: 1, 5, 7
Factors of 49, 1, 7

The common factors between the three numbers are 1 and 7, but we are looking for the greatest common factor, not the common ones. It either has to be 1 or 7, and 7 is obviously the highest, making it the greatest common factor.
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Rosa throws a ball. The equation d = −t^2 + 4t + 5 represents the path taken by Rosa's ball where d is the height of the ball (i
satela [25.4K]

Answer:

B

Step-by-step explanation:

-t²+4t+5=0

t²-4t-5=0

t²-5t+t-5=0

t(t-5)+1(t-5)=0

(t-5)(t+1)=0

t=5,-1

when t=0,d=5

actual time it it is in air=5-1=4 seconds.

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Step-by-step explanation:

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Sammy has a 10-foot ladder, which he needs to climb to reach the roof of his house. the roof is 12 feet above the ground.
Dvinal [7]
<span>The roof is higher than the ladder can reach 10^2-1.5^2=h^2 h=sqrt(100-2.25)=9.89 feet distance to the roof= 12-9.89</span>
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4 years ago
In Salem, 82% of the households have cable television and Internet access and 90% of the houses have cable television. What is t
Alekssandra [29.7K]
The formula for conditional probability is:
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3 years ago
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Let v1,....., vk be vectors, and suppose that a point mass of m1,....., mk is located at the tip of each vector. The center of m
a_sh-v [17]

Answer: m1 = 4

m2 = 5

m3 = 2

Step-by-step explanation:

given (21/11, 6/11) = m1 (-1/3) + m2 (3, -2) + m3 (5, 2)

= (-m1 + 3m2 + 5m3) / 11 = 21/11

= (3m1 + (-2)m2 + 2m3) / 11 = 6/11

so that m1 + m2 +m3 = 11

-m1 + 3m2 + 5m3 = 21

3m1 - 2m2 + 2m3 = 6

from this, we get the augmented matrix as

\left[\begin{array}{cccc}-1&1&1&11\\-1&3&5&21\\3&-2&2&6\end{array}\right]

= \left[\begin{array{cccc}-1&1&1&11\\0&4&6&32\\0&-5&-1&-27\end{array}\right]  \left \{ {{R2=R2 + R1} \atop {R3=R3 -3R1 }]} \right.

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&-5&-1&-27\end{array}\right]

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&0&13/2&13\end{array}\right]

(R3 = R3 + 5R2)

this gives m1 + m2 + m3 = 11

m2 + 3/2 m3 = 8

13/2 m3 = 8

13/2 m3 = 13

m3 = 2

m2 = 8 -3/2 (2) = 5

= m1 = 11- 5 - 2 = 4

this gives

m1 = 4

m2 = 5

m3 = 2

4 0
3 years ago
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