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wariber [46]
3 years ago
10

Solve 3x2 + 18x + 15 = 0 by completing the square.

Mathematics
1 answer:
kondaur [170]3 years ago
3 0
<span>3x^2 + 18x + 15 = 0
15 + 18x + 3x2 = 0
3(5 + 6x + x2) = 0
</span>3((5 + x)(1 + x)) = 0
5 + x = 0
5 + -5 + x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + x = 0 + -5 x = 0 + -5
x = -5
<span>--------------------------------------------
1 + x = 0 x=-1
-5,-1 </span>
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Radius and diame
makvit [3.9K]

Answer:

d = 4 units

Step-by-step explanation:

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5 0
3 years ago
How many different rectangles can you draw, that has an area of 28 cm sq. ? pls help me
jolli1 [7]

Answer:

You can draw three rectangles:

1- 28 * 1.

2- 14*2

3- 7*4

Step-by-step explanation:

We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.

28 = 1*2*2*7

We can organize them as follows:

R1: 28 = 1*28

R2: 28 = 2*14

R3: 28 = 4*7

Finally, we can conclude that there are only three possibilities

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2- 14 by 2

3- 7 by4

The perimeters will be:

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3 0
3 years ago
Solve the inequality
GenaCL600 [577]
-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
============================
6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2

-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6

so y > = 9/6(or 1 1/2) or y < = -6


3 0
3 years ago
Two boys searching for buried treasure are standing underneath the same tree. one boy walks 12 m east and then 12 m north. the o
mylen [45]
Let
 The origin of coordinates the tree
 r1 = vector position of the child 1.
 r2 = vector position of the child 2
 Child 1:
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 Child 2:
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 The scalar product of their net displacements from the tree is -84m ^ 2
5 0
3 years ago
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