The running time for an input size of 1000 will be 25 seconds.
To calculate the runtime of the Algorithm we need to know what an Algorithm is and how its runtime works.
<h3>What is the runtime of an
Algorithm?</h3>
A finite sequence of rigorous instructions, used to solve a critical problem of a specific class or for computational purposes is called an Algorithm. The time taken to complete the said task is called the runtime of an Algorithm.
Let us now solve the question about linear running time of an algorithm.
Input size(
)=200
Time taken(
)=5 seconds
Final input size(
)=1000
Let the final time taken be T.
Now we know that: 
Substituting the values we get 
seconds .
Therefore the linear running time for an input size of 1000 is 25 seconds.
To know more about Algorithm:
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Y=mx+b
2=4×1+b
2=4+b
-2=b
Equation/ y=4x-2
2A)
C is correct.
2B) If x + 13 = 28, solve.
If x = 15 and x + 13 = 28, you can solve it two ways:
1. Plug x into 4x + 26 to get a perimeter of
86, or
2. Redo the equation:
3a. Since the 6z is negative, you want an expression the has 5z - (11z). Answers A and D have that in their answer.
But since the 13 is positive, you want the answer that subtracts the smaller number from the larger. Thus,
D is your answer since it subtracts 2 from 15.
3b) You think about this question the same way; 6z is positive, so the smaller number is being subtracted from the larger, meaning that 11z - 5z is what you look for. C and D are the two that have that, so now let's look at the second term.
The 13 is negative, so you want the answer that has 2 - 15. The answer that has that is
D.
Hope this helps :D
Step-by-step explanation:
y=kxz
13=k x 5 x 8
13= 40k
K=13/40
a. y=13/40 x 4 x 10
y=13/40 x 40
y=13
b. 20=13/40 x x x 12
20=13/40 x 12x
20=<u>156x</u>
40
20 x 40=156x
800=156x
X=<u>800</u>
156
X=<u>200</u>
39
X=5 5/39
C. 15=13/40 x 6 x z
15=<u>78z</u>
40
15x40=78z
600=78z
Z=<u>600</u>
78
Z=<u>100</u>
3
Z=7 9/13
Answer:
∠HGJ and ∠KJL
Step-by-step explanation:
Corresponding angles are on the same side of the transversal where it cuts the two parallel lines, they have the same measure.
