Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
Answer:
23
Step-by-step explanation:
We are given that
f(2)=13


We have to find the possible small value of f(7).
We know that

Using the formula


We have






The small value of f(7) can be 23.
Answer:
x = 2
Step-by-step explanation:
The solution set can be found by dividing the inequality by the coefficient of x.
6x > 7
x > 7/6
The smallest integer greater than 7/6 is 12/6 = 2.
The smallest integer solution is x = 2.
The mean is: 7.6
The range is: 7
The median is: 7
The mode is: 5
:)
Option C, 36, because it is the LCM (Least common multiple)