Answer:
-3
Step-by-step explanation:
Answer: x log[5] = log[125]
Explanation:
The original expression is 125 = 5^x
To express that as a logarithmic equation take logarithms on both sides:
log [125] = [log 5^x]
By the properties of the logartims of powers that is:
log [125] = x log[5]
And that is the equation required.
If you want to solve it, you can do 125 = 5^2, and apply the same property (logarithm of a power) to the left side, yielding to:
log [5^2 ]= x log[5]
=> 2 log[5] = x log[5]
=> 2 = x
Answer:
A.) x / 3 = 12 ----> x = 12(3) ----><em> </em><em>x = 36</em>
B.) 2x + 3 = 20 ----> 2x = 17 ----> x = 17/2
C.) 4/3x = 10/3 ----> x = 10/3 x 3/4 ----> x = 30/12 = 5/2
D.) -4x = -24 ----> x = -24/-4 ----> x = 6
E.) 2(x-4) = 10 ----> 2x - 8 = 10 ----> 2x = 18 ----> x = 9
F.) -0.5x + 1.1 = -2.9 ----> -0.5x = -4 ---> x = -4 / -0.5 ----> x = 8
Answer: I do not have expertise on this so I won't answer the exact problem but this sounds like exponential decay, where you have the decay rate. I know that the formula for exponential decay is: y = a(1 - r)^x
I'm sorry if this does not help much I don't have expertise on this. Sorry again.
Step-by-step explanation:
The formula of the future value of annuity ordinary is
Fv=pmt [(1+r/k)^(kn)-1)÷(r/k)]
Fv future value?
PMT payment 6200
r interest rate 0.06
K compounded semiannual 2
N time 5 years
Fv=6,200×(((1+0.06÷2)^(2×5)) ÷(0.06÷2))=277,742.72
Hope it helps
