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3 years ago

Rewrite the equation in slope-intercept form, identify slope, and the y-intercept of the line.

2 answers:

7 0

Rearrange equation to get y as subject
-1x-10y = 20
10y = -1x - 20
y = -1x/10 -2

so the slope is -1/10 and the y intercept -2

Elza [17]3 years ago

3 0

$-x-10y=20\\
-10y=x+20\\
\boxed{y=-\frac{1}{10}x-2}\\\\
\boxed{m=-\frac{1}{10}}\\\\
-0-10y=20\\
-10y=20\\
\boxed{y=-2}
$

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If you flip a coin 4 times, what is the best prediction possible for the number of times it will land on tails?

allochka39001 [22]

Answer:

Step-by-step explanation:

Each time you flip a coin, there is a 50% change of it landing on tails. So half the time you should get a tails.

Half of 4 is 2, so you will likely get 2 tails.

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3 years ago

A shopkeeper buys pens at the rate of ₹ 75 per 100. for how much should he sell each pen so as to make a gain of 15%? please hel

Lady bird [3.3K]

Answer:

He should sell each pen of Rs.0.8625 so as to make a gain of 15%

Step-by-step explanation:

Cost price of 100 pens = Rs.75

Cost price of 1 pen= $\frac{75}{100}$ = 0.75

Gain%= 15%

Gain= $15%$ $X 0.75$ $= 0.1125$

SP = CP+Gain = 0.75+0.1125=0.8625

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#Learn more:

By selling 60 pens a shopkeeper gain the cp of 15 pen. If he bought 20 pens in rs36. Find the sp of one pen

brainly.in/question/15083989

https://brainly.in/question/7469007

3 0

3 years ago

HELP NEED ASAP FOR TOMORROW ITS FOR MY HOMEWORK!! ILL MARK BRAINLIEST IF RIGHT!!

Slav-nsk [51]

Answer:

y ≥ -x +2

Step-by-step explanation:

The solid line has a slope of -1 and a y-intercept of 2, so its equation in slope-intercept form is ...

y = -x +2

The shaded area is above this line, and the line is part of the solution set, so we want an inequality that has "y" and the comparison symbol in this order: "y ≥" or "≤ y".

We already have an equation with "y" on the left, above, so we just need to introduce the comparison symbol:

y ≥ -x +2

Another way to write this is ...

x + y ≥ 2

4 0

3 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

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3 0

3 years ago

Using addition formula solve tan 15

salantis [7]

Answer:

2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = $\frac{tanA-tanB}{1+tanAtanB}$ and the exact values

tan45° = 1 , tan60° = $\sqrt{3}$ , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

= $\frac{\sqrt{3}-1 }{1+\sqrt{3} }$

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

= 2 - $\sqrt{3}$

3 0

3 years ago