All categories

3 years ago

Basketball shoes are on sale for 22%off. what is the reagular price if the sale price is $42?

Mathematics

1 answer:

Brrunno [24]3 years ago

4 0

Answer:

The regular price was $53.85

Step-by-step explanation:

78% = $42

42 ÷ 78 x 100 = 100% = $53.85 (when rounded to 2 d.p)

You might be interested in

Find the value of x. Brainlest for anyone who answers and explains it!

sergejj [24]

Answer:

x=-2

Step-by-step explanation:

Since it is an equilateral triangle (note the little lines across the legs of corner 2) the other angle must be 69° as well.

That leaves 180-69-69 = 42 for ∠2.

So x + 44 = 42 => x = 42-44 = -2.

3 0

3 years ago

3-9x=6×7x(10÷5(4+3³)+2x)

nasty-shy [4]

Answer:

871 - \sqrt(758753)) (56) (871+\sqrt(758753)) (56) decimal form: 0.00114806, -31.0829092

Step-by-step explanation:

5 0

3 years ago

When it is raining outside, you tend to stay in and watch TV. The number of hours of TV that you watch in a given week is twice

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

the answer is 74

7 0

3 years ago

How much water must be evaporated from 32 ounces of a 7% salt solution to make a 8% salt solution. Answer in ounces.

Nadya [2.5K]

You subtract 7% from 32=29.76
Then you subtract 8% from 29.76=27.379

7 0

3 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

3 years ago