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aksik [14]
3 years ago
9

Jen bought 5 CDs for $57.50, what was the unit price

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

$11.50. Each CD cost $11.50.

Step-by-step explanation:

When trying to determine how much each CD cost, we need to know our total cost, $57.50, and how many CDs were bought, 5.

Since 5 CDs cost $57.50, we can divide our total cost by the number of CDs purchased to find the cost of each CD. 57.50 / 5 = 11.50

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Please answer the question from the attachment.
krek1111 [17]
Y + -4 = 9  (this means y plus negative 4 equals 9)

y -4 = 9
  +4    +4

y  = 13



7 0
3 years ago
Nine is 4 percent of what number
Katarina [22]

Answer:

225

Step-by-step explanation:

We can model this question with:

9 = 0.04x

x represents "what number."

0.04x = 9.

Divide 0.04 from both sides

0.04x ÷ 0.04 = 9 ÷ 0.04

9 ÷ 0.04 = 225.

Therefore, 9 is 4% of 225.

5 0
3 years ago
Read 2 more answers
Philip is conducting a survey to determine the weight of 100 cows on a farm. Which of the following questions is an appropriate
liubo4ka [24]
Because Philip is conducting a survey that pertains to the weight of the cows, he needs statistics that directly relate to weight.

The cows being overweight doesn't give Philip concrete information on the weight of the cows, as it doesn't give the amount of pounds a cow weighs. Average age has nothing to do with weight, and normal body weight doesn't give concrete information on weight.

The answer is "<span>What is the weight of each cow on the farm?".</span>
5 0
3 years ago
Read 2 more answers
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
Which expressions will help you find the surface area of this net? Select all that apply.
Ierofanga [76]
<h3>9 × 6</h3>

Because the surface area is rectangle and the area of rectangle is length × width

length = 9

width = 6.

so 9×6

8 0
3 years ago
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