- Points J, K, and Q are collinear
- There is only one line that can be drawn through points L and P
A = 1/2 (b x h)
A = 1/2(12.5 x 2.4)
A = 1/2(30)
A = 15
DEF= 6 ft^2
A= 1/2*b*h
Plug in what you know.
6= 1/2*4*h
Multiply like terms.
6=2*h
Divide 2 on both sides.
3=h
If the base of ABC= 12
12/4=3
3*3=9
A= 1/2*b*h
A= 1/2*12*9
A= 1/2*84
A= 42
The area of ABC is 42 ft^2
I hope this helps!
~kaikers
If you use a ruler and if it's more than 120° its not a right triangle it has to be 120°
Answer:
x = pi/2 + 2 pi n x = pi + 2 pi n where n is an integer
x = 5pi /3 + 2 pi n
Step-by-step explanation:
8 cos^2 x + 4 cos x-4 = 0
Divide by 4
2 cos^2 x + cos x-1 = 0
Let u = cos x
2 u^2 +u -1 =0
Factor
(2u -1) ( u+1) = 0
Using the zero product property
2u-1 =0 u+1 =0
u = 1/2 u = -1
Substitute cosx for u
cos x = 1/2 cos x = -1
Take the inverse cos on each side
cos ^-1(cos x) = cos ^-1(1/2) cos ^-1( cos x) =cos ^-1( -1)
x = pi/2 + 2 pi n x = pi + 2 pi n where n is an integer
x = 5pi /3 + 2 pi n