2 years ago

Find the following when a = -1, b = 2, c = -1/4 (4b - 3)/(2a) -1

Mathematics

1 answer:

jekas [21]2 years ago

5 0

Already asked question.
But anyways, see the attachment i have added below.
I have it typed there

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Help! im confuseddd!!!!!!!!!!

Assoli18 [71]

Answer:

sin B= square root of 3/ 2

Cos B= 1/2

tan B= square root of 3/1

Sin C=1/2

cos C square root of 3/2

tan C= 1/square root of 3

Step-by-step explanation:

4 0

2 years ago

What is sarah is twice as old as her youngest brother. if the difference between their ages is 15 years. how old is her youngest

r-ruslan [8.4K]

Her youngest brother is 15 years old.

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3 years ago

An object falls from a height of 400 feet. Its height, h, in feet is given by the equation h=-16t^2+400 , where t is the time in

LekaFEV [45]

16t^2=400
t^2=25
t=5
5 seconds=B

6 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

Can I get some help on this problem

kow [346]

Answer:

Gas left after 5 hours is: 10 gallons

Gas left after t hours is : sorry I don't know

Step-by-step explanation:

Subtract 2 everytime you count an hour

Hope this helps

3 0

2 years ago