Let x be the large number, and y be the smaller one: x=3+2y, 2x-5y=0 (from the question) --> substitute the first equation in the second --> 2(3+2y)-5y=0 --> 6+4y-5y=0 -->6-y=0 --> y=6, substitute y=6 in the first equation --> x=3+2(6) --> x=15. therefore the two numbers are 6,15
The circumference is 131.95 and the area is 1385.44
Answer:
Infinite solutions.
Step-by-step explanation:
Let's solve your system by substitution.
3y=9x+15;3x−y=−5
Rewrite equations:
3x−y=−5;3y=9x+15
Step: Solve 3x−y=−5 for y:
3x−y=−5
3x−y+−3x=−5+−3x(Add -3x to both sides)
−y=−3x−5
−y −1 −1=−3x−5
(Divide both sides by -1)
y=3x+5
Step: Substitute 3x+5 for y in 3y=9x+15:
3y=9x+15
3(3x+5)=9x+15
9x+15=9x+15(Simplify both sides of the equation)
9x+15+−9x=9x+15+−9x(Add -9x to both sides)
15=15
15+−15=15+−15(Add -15 to both sides)
0=0
Hello lucker
<span> graph of y = [x] for -2 ≤ x ≤ 2 </span>
Answer:
12
Step-by-step explanation:
first multiply 6 and 4.
then divide by 2.
