Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
=
Step-by-step explanation:
Answer:
10.06 ft
Step-by-step explanation:
Maria's maximum height will occur when her velocity reaches zero (0). This means that she has stopped ascending and is about to begin descent.
The equation for the height reached by Maria on the trampoline is given as:
To find her maximum height, we first have to find the time it will take her to get to that height and corresponding velocity (zero).
Her velocity can be found by differentiating her height i.e. dh/dt:
Therefore, when v = 0:
It takes her 0.5625 seconds to get to her maximum height.
Therefore, her height at that time (0.5625 seconds) is:
Therefore, her maximum height is 10.06 ft.
