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grin007 [14]
3 years ago
6

How many km per hour must you swim if you want to cross a 5-km channel in 4 hours?

Mathematics
2 answers:
ELEN [110]3 years ago
6 0
The amount you mus swim is 1.25 km an hour

hodyreva [135]3 years ago
5 0
The actual answers is that you would have to swim at 1.25 mph to reach your goal. 48 minutes pet km!
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PLEASE HELP For BRAINLIEST ANSWER
Anna35 [415]
You do this
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4 years ago
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In a fibonacci sequence the fourth term is 30 and the fifth is 49 what is the first term
scoundrel [369]

8 is the first.

Reasoning:

So we know what the Fibonacci sequence is. To get the next number, you add the number behind it, by the number behind that.

For example, these are the first 5 Fibonacci numbers.

1, 1, 2, 3, 5.

1 + 0 = 1.

So 1 is the second number.

1 + 1 is 2.

So 2 is the third number.

2 + 1 = 3.

So 3 is the fourth number.

3 + 2 = 5.

So 5 is the fourth number.

The problem:

If the fifth term is 49, and the fourth term is 30. We can subtract 49 by 30, to find the third number, and so on.

49 - 30 = 19.

So 19 is the third number.

30 - 19 = 11.

11 is the second.

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8 is the first.

7 0
4 years ago
A cylinder has a height of 14 centimeters and a radius of 17 centimeters. What is its volume? Use ​ ≈ 3.14 and round your answer
9966 [12]
<h2><u>Answer</u></h2>

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6 0
3 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

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3 years ago
Explain how you could show five less than a number using an expression.
Assoli18 [71]
If the number was x, then you could write the expression x-5 since you show five less or subtracted from the number. Hope this helps. 
6 0
3 years ago
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