Answer:
Step-by-step explanation:
4^x-5 = 6
<u>Apply the ln rule</u>
x^y = z
(y)*ln(x) = z
4^x-5 = 6
(x-5)*ln(4) = ln(6)
x-5 = ln(6)/ln(4)
x-5 = 1.292
x = 6.292
Therefore, the correct answer is the last option.
!!
Answer:
- Timmy has successfully shown Suzie's conjecture is incorrect
- Suzie's conjecture is correct if the smallest square in the sum is 1
Step-by-step explanation:
The sum of odd numbers 1 .. n is ((n+1)/2)², a perfect square. Suzie is right about that. What Timmy has shown is that she is incorrect that the conjecture applies to <em>any</em> sum of consecutive odd numbers.
Timmy's sum of 5+7+9 is incorrect; it is 3·7 = 21. But, Timmy has the right idea. The sum of an arbitrary set of consecutive odd numbers will be the difference of two squares, but not necessarily a perfect square.
Volume of container = <span>π x 4^2 x 6/4 = 75.40 cubic units
volume of empty space = volume of box - volume of container = 96 - 75.40 = 20.60 cubic units
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Answer:
I'd say that is an "occupancy problem".
I ran a spreadsheet simulation of that and I'd say the probability is approximately .13
Those problems are rather complex to solve. What I think you would have to do is calculate the probability of
A) ZERO sixes appearing in 4 rolls.
B) exactly 1 six appears in 4 rolls.
C) exactly 2 sixes appear in 4 rolls.
D) exactly 3 sixes appear in 4 rolls. and
E) exactly 4 sixes appear in 4 rolls.
4 rolls of a die can produce 6^4 or 1,296 combinations.
A) is rather easy to calculate: The probability of NOT rolling a six in one roll is 5/6. In 4 rolls it would be (5/6)^4 = 0.4822530864
E) is fairly easy to calculate: The probability of rolling one six is (1/6). The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049
Then we need to:
D) calculate how many ways can we place 3 objects into 4 bins
C) calculate how many ways can we place 2 objects into 4 bins
B) calculate how many ways can we place 1 objects into 4 bins
I don't know how to calculate D C and B
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
