In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 8x^3+2/2x^3+x
1 answer:
Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))
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<span>3 cans store
9 tennis balls.
Find the Constant of proportionality and write and equation with regards to this given situation:
=> number of tennis balls = 9
=> number of cans = 3
</span> <span>So the constant of proportionality is in the working column. Pls see attached.<span>
</span></span>
Find the Constant of proportionality and write and equation with regards to this given situation:
=> number of tennis balls = 9
=> number of cans = 3
</span> <span>So the constant of proportionality is in the working column. Pls see attached.<span>
</span></span>
There you go, the answer is circled. The rest is the work that goes to it.
