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Degger [83]
3 years ago
7

In Exercise,find the horizontal asymptote of the graph of the function. f(x) = 8x^3+2/2x^3+x

Mathematics
1 answer:
KIM [24]3 years ago
6 0

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

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