Answer:
Step-by-step explanation:
if m and n are irrational number then the product of mn sometimes rational and sometime irrational
ex: √5 *√2=√10 irrational
ex: √8*√2=√16=4 rational
b-y=|x|+3
explain why |x|+3≥|x+3|
absolute value of any number is always positive
x |x|+3 ≥ |x+3|
1 4 = 4 in this case equal
2 5 5
-2 5 ≥ 1 in this case |x|+3≥|x+3|
in case of negative value of x then |x|+3>|x+3|
Answer:
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
