Standard error of the mean is computed by:
Standard error = SD/ sqrt N
Where:
N is the sample size
SD is the standard deviation
To get the standard deviation, you need to get the sqrt of
the variance = sqrt 9 = 3
So plugging in our data:
Standard error = 3 / sqrt (16)
= 0.75
Answer:
46°
Step-by-step explanation:
BE is the bisector so abe is the same as ebc
2x+20=4x-6
26=2x
13=x
so now plug x back into abe to find its measure
2(13)+20
26+20
46
Answer and Step-by-step explanation:
Ok, it's basically just parts of a circle circumference and area equation. Let's start first by writing down both equations.
C = 2πr
C = πd
A = π
Now, all we have to do is plug in the values into those equations!
4. C = 2π(12) A = π(
)
r = 12
d = 24 <---- (12 times 2 equals 24)
C = 24π
A = 144π <---- (12 times 12 (itself) equals 144)
5. C = π4.8 A = π(
)
r = 2.4 <------- (4.8 divided by 2 equals 2.4)
d = 4.8
C = 4.8π
A = 23.04π <------- (4.8 times 4.8 equals 23.04)
6. 20π = 2πr A = π
r = 10 <------- (20π divided by π and divided by 2)
d = 20 <------- (20π divided by π)
C = 20π
A = 100π <------- (10 times 10 equals 100)
7. C = 2πr 81π = π
r = 9 <------- (81π divided by π and square rooted equals 9)
d = 18 <------- (9 times 2 equals 18)
C = 18π <------- (2 times 9 equals 18, times π)
A = 81π
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Answer:
1st statement is true.
2nd statement is false.
3rd statement is true.
Step-by-step explanation:
We have been given two inequalities and we are asked to find out whether the given statements are true or false.
represents balance of account A and
represents balance of account B.
1. We can see from our inequalities that Jeremiah initially invested $100 in account A and $50 in account B. Therefore, 1st statement is true.
2. The rate at which balance of account A grows is 1.2 and rate for account B is 1.23. Therefore, 2nd statement is false.
3. We can find total amount Jeremiah invested in two accounts by adding initial investment of both accounts, that is 100+50=150 . Therefore, 3rd statement is true.