Answer : The specific heat of the metal is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of ice = 
= mass of metal = 1.00 kg
= mass of ice = 1.00 kg
= final temperature of mixture = 
= initial temperature of metal = 
= initial temperature of ice = 
Now put all the given values in the above formula, we get:
![(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]](https://tex.z-dn.net/?f=%281.00kg%29%5Ctimes%20c_1%5Ctimes%20%28-8.88-5.00%29%5EoC%3D-%5B%281.00kg%29%5Ctimes%202000J%2Fkg%5EoC%5Ctimes%20%28-8.88-%28-24.0%29%29%5EoC%5D)
Therefore, the specific heat of the metal is,
Answer:
y=11/3
Step-by-step explanation:
3y=2+9
Divide both sides by 3.
3y/3 = (2+9)/3
y=2/3+9/3
Combine like terms.
<u>y=11/3</u>
70,000
The 0 means that it stays the same.
Hope it helps.
Answer:
m/3
Step-by-step explanation:
13 m or m 3
Explanation:One third = 13 (the number)'Of' = multiplication (symbol : ×)
a number m = m (variable)
One third of a number m= (one third)(a number m)= (13)(a variable) = (13)
(m)= 13 m or m 3 since 13 m = m/3
19 is the median of the numbers
