Alexis bought a pyramid-like paperweight for her teacher. The paperweight has a volume of 200 cm3 and a density of 1.5 grams per
1 answer:
Answer:
The density is equal to the weight divided by the volume:
The paperweight weights 300 grams.
Step-by-step explanation:
The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.
The density is equal to the weight divided by the volume:
We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.
We can use the formula of the density to calculate the weight:
The paperweight weights 300 grams.
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we are given one of the points and the center
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points (-3,2) and (1,5)
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input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
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y-2=+/-3
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y=2+/-3
y=5 or -1
the point (-7,5) and (7,-1) lie on this circle
radius=5 units
the points (-7,5) and (-7,1) lie on this circle
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius
to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=
points (-3,2) and (1,5)
D=
D=
D=
D=
D=5
center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1
the point (-7,5) and (7,-1) lie on this circle
radius=5 units
the points (-7,5) and (-7,1) lie on this circle