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3 years ago

Write the following expression in radical form

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

Answer:

See below

Step-by-step explanation:

Write the following expression in radical form

(8x)¹/² = $\sqrt{8x}$

Write the following expression in exponential form.

$\sqrt{19}$ = 19¹/²

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Mike's grandmother opened a savings account in Mike's name and deposited some money into the account. The account pays an annual

Snowcat [4.5K]

SI = prt/100
1440 = (p*9*8)/100
⇒p=2000

7 0

3 years ago

a square garden has a diagonal of 12 m. What is the perimeter of the garden? Express in simplest radical form

lianna [129]

Answer:

The perimeter of the garden, in meters, is $24\sqrt{2}$

Step-by-step explanation:

Diagonal of a square:

The diagonal of a square is found applying the Pythagorean Theorem.

The diagonal of the square is the hypothenuse, while we have two sides.

Diagonal of 12m:

This means that $d = 12$ , side s. So

$s^2 + s^2 = 12^2$

$2s^2 = 144$

$s^2 = \frac{144}{2}$

$s^2 = 72$

$s = \sqrt{72}$

Factoring 72:

Factoring 72 into prime factors, we have that:

72|2

36|2

18|2

9|3

3|3

$72 = 2^{3}*3^{2}$

So, in simplest radical form:

$s = \sqrt{72} = \sqrt{2^{3}*3^{2}} = \sqrt{2^3}*\sqrt{3^2} = 2\sqrt{2}*3 = 6\sqrt{2}$

Perimeter of the garden:

The perimeter of a square with side of s units is given by:

$P = 4s$

In this question, since $s = 6\sqrt{2}$

$P = 4s = 4*6\sqrt{2} = 24\sqrt{2}$

The perimeter of the garden, in meters, is $24\sqrt{2}$

5 0

2 years ago

What is the product of (a-5) and (a+3)

abruzzese [7]

= (a-5).(a+3) = a²+3a-5a-15 = a²-2a-15

3 0

2 years ago

Use the general solution to solve 5 – 6x = 8x + 17.

Jlenok [28]

5 – 6x = 8x + 17
⇔ 5 - 17 = 8x + 6x
⇔ -12 = 14x
⇔ x = -6/7

7 0

3 years ago

Read 2 more answers

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 411 gram setting. It

nikdorinn [45]

Answer:

0.0445937

Step-by-step explanation:

-Given that the sample statistic has a mean of 406 grams, standard deviation of sq root(225) and the null statistic is 411 grams.

-Assuming normal distribution, the test statistic is calculated as:

$z=\frac{Sample \ statistic-Null \ statistic}{\sigma/\sqrt{n}}\\\\=\frac{406-411}{\sqrt{225/26}}\\\\=-1.6997$

-we then find the p-value of the test statistic from the z-tables:

P-value=0.0445937

8 0

3 years ago