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kkurt [141]
3 years ago
12

What are the surface area of each cylinder

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0
It looks messy and blury 

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2. Rosa and her friends went kayaking at a local lake. Rosa paid $12 for
Alinara [238K]

Answer:

THREE HOURS

Step-by-step explanation:

34.50-12=22.5

22.5/7.50=

=3

5 0
3 years ago
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2x - 2y = 2 and 7 = -x​
Elina [12.6K]

Answer:

y = -6

Step-by-step explanation:

6 0
3 years ago
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Please solve these soon I have to turn thin in tomorrow !!!!!!!!
Gnoma [55]

Answer:

a) so if you're looking for a then you substitute the a in the problem so the real question would be answered by simply doing this. 3 times (do this first) 6 times 3. so it would end up looking like this if you did it in your head. 6x3=18 then 18x3= 54 so the answer for ten after you did all the math would equal out to be 54.

d) so you're going to substitue the d again, for what it tells you d equals. in this case, d= a negative 2 so, 5 x do this first -2 x 4 = so if you did this in your head you would end up with -2 x 4 = -8 because anything times a negative is turned into a negative. so that is why the answer is -8 for the first part. then you multiply that answer by 5 because we all like the 5 dollar foot longs. so carry that into an answer of - 40. because we all know we want to be younger once we reach 40.

r) 5times -3 equals -15 times 2 would be... ding ding ding 30 because a negative times a negative is a positive. think of negatives this way. when you frown it's your smile upside down. ok so a frown is a negative, if you multiply a negative to a negative it's like turning your frown upside down. so you end up with a positive! ok?! so there. the secrets of life and math.

call me for the rest of the answers... this is too much to write down.

Step-by-step explanation:


4 0
3 years ago
3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W
kenny6666 [7]

Answer:  The proof is done below.

Step-by-step explanation:  Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U  and  x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0
3 years ago
Which of the following statements is NOT true about the linear equation, y+3=-2(x-7)
pochemuha

Answer:

There is no options this is unclear

Step-by-step explanation:

5 0
3 years ago
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