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3 years ago

What is the slope of a line perpendicular to the line whose equation is x-3y=-6x−3y=−6

Mathematics

1 answer:

marissa [1.9K]3 years ago

7 0

Answer:

- 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 3y = - 6 into this form

Subtract x from both sides

- 3y = - x - 6 ( divide all terms by - 3 )

y = $\frac{1}{3}$ x + 2 ← in slope- intercept form

with slope m = $\frac{1}{3}$

Given the slope m of a line then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3

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3 years ago

The correct answer is D but i don’t understand

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The answer depends on the way you solved it.

I am assuming you take the base on which you perceived to be: . 5 and height which is 2.

So you must've ended with 1

But in actuality, you need to use the equation above and plug in 1.5 and 1
Subtract them and you should get 1.25

Do the same to the other side, you should get 6.

.125 x 6 = .875

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What is the slope of a line perpendicular to the line whose equation is x-3y=-6x−3y=−6​

What is the slope of a line perpendicular to the line whose equation is x-3y=-6x−3y=−6