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Sedaia [141]
3 years ago
15

What is the slope of a line perpendicular to the line whose equation is x-3y=-6x−3y=−6​

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

- 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 3y = - 6 into this form

Subtract x from both sides

- 3y = - x - 6 ( divide all terms by - 3 )

y = \frac{1}{3} x + 2 ← in slope- intercept form

with slope m = \frac{1}{3}

Given the slope m of a line then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{3} } = - 3

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