Answer:
0.91517
Step-by-step explanation:
Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.
Let A - the event passing in SAT with atleast 1500
B - getting award i.e getting atleast 1350
Required probability = P(B/A)
= P(X>1500)/P(X>1350)
X is N (1100, 200)
Corresponding Z score = 
Answer:
12.05
Reason:
8.6
+3.45
————-
12.05
Don’t forget to carry the one to the left
6+4= 10 carry the one to the left.
8+3+1 = 8+4 =12
Answer 12.05
X equals 5 so 3x+4= 19 ..................
The percentage when Potiphar woke up late is 14.4%.
<h3>How to calculate the percentage?</h3>
From the information, it was stated that Potiphar takes a horse and buggy to work everyday. In order to come on time, he must wake up promptly at 6.30am and then hop on the buggy and that anytime he wakes up late or the horse was in traffic, he will be late.
It was further illustrated based on the information given in the question that he was late 24.4% of the time and the horse was in traffic for 10% of the time.
Therefore, the percentage when he woke up late will be gotten by simply subtracting the percentages that we have above. This will be illustrated below:
= 24.4% - 10%
= 14.4%
Therefore, the percentage when Potiphar woke up late is 14.4%.
Learn more about percentages on:
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