Answer:
x= 60.4
Step-by-step explanation:
y = 60.4
z= 29.6
x= 60.4
By complementary angle rule
Answer:
The answer is below
Step-by-step explanation:
A tangent is a line which touches a circle at one point. The angle between a tangent and a circle is 90°.
The two tangent theorem states that tangent that meet at the same point are equal in length.
Therefore:
CD = c + d
but c = 5.1, hence:
CD = 5.1 + d
12.1 = 5.1 + d
d = 7
AD = a + d; but AD = 12.2, d = 7
12.2 = a + 7
a = 5.2
AB = a + b; but b = 3.3
AB = 5.2 + 3.3 = 8.5
BC = b + c = 3.3 + 5.1 = 8.4
Perimeter of ABCD = AB + BC + CD + AD = 8.5 + 8.4 + 12.1 + 12.2 = 41.2
Using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.
<h3>What is the
distance formula?</h3>
Distance formula for calculating the distance between two points on a coordinate plane is given as:
.
Let,
(-3, 4) = (x1, y1)
(2, -3) = (x2, y2)
Plug in the values

c = 8.6 units.
Therefore, using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.
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Answer:
y=13
Step-by-step explanation:
5+13=18
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
Learn more about adiabatic expansion on:
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