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musickatia [10]
3 years ago
8

Adam has three pennies, two dimes, and one nickel. he also has one other coin that is different from the rest of his coins. how

much could he have?
Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

Step 1. Read the problem. Make sure you understand all the words and ideas.

Step 2. Identify what you are looking for.

Step 3. Name what you are looking for.

Step 4. Translate into an equation. Restate the problem in one sentence. Then translate into an equation.

Step 5. Solve the equation using good algebra techniques.

Step 6. Check.

Step 7. Answer the question.

Step-by-step explanation:

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Translate the sentence into an equation.
zavuch27 [327]
Answer:
2*(b-6)=8

Explication:
1.divide both sides by 2
b - 6 = 4

2. move the constant to the right and change the sign
b= 4 + 6

3. Calculate
b= 10

7 0
3 years ago
Which of the following describes what happens when you change the a value in the equation shown below?
Over [174]
I will say that it is C
7 0
3 years ago
Read 2 more answers
If w = -2 and v = -8, which of the following expressions shows the values correctly substituted in for the variables in the expr
ki77a [65]

Answer:

the first one

(-2) 2-(-8)+1

3 0
2 years ago
Read 2 more answers
5-7k=-4(k+1)-3 add work pleasee!!!
marshall27 [118]

Answer:

k=4

Step-by-step explanation:

5-7k=-4(k+1)-3

Distribute

5-7k=-4k-4-3

Combine like terms

5-7k=-4k-7

Add 7k to each side

5-7k +7k = -4k+7k-7

5 = 3k-7

Add 7 to each side

5+7 = 3k-7+7

12 = 3k

Divide by 3

12/3 = 3k/3

4=k

3 0
2 years ago
Read 2 more answers
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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