Here are the answer: a) R = 3.6 and b) A = 2
Step-by-step explanation:
Given,
R is inversely proportional to A.
R ∝ 
so, R =
-------eq 1 where k is any constant
To find the values of a) R when A = 5 and
b) Value of A when R = 9
Now,
Putting R = 12 and A = 1.5 in eq 1 we get,
12 = 
or, k = 12×1.5 = 18
From eq 1 we get,
R =
--------- eq 2
Now,
a) Putting A= 5 in eq 2 we get,
R =
= 3.6
b) Putting R = 9 in eq 2 we get
R =
or, A =
= 2
Answer:
the answer is d!
Step-by-step explanation:
because the radius is measuring the distance from any point on the circle to the very center of the circle
Answer: Choice C) 124 square cm
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Explanation:
Let's calculate the area of the trapezoid shown
b1 and b2 are the parallel bases; h is the height of the 2D trapezoid
b1 = 2
b2 = 5
h = 1.5
A = h*(b1+b2)/2
A = 1.5*(2+5)/2
A = 1.5*7/2
A = 10.5/2
A = 5.25
The area of one 2D trapezoid is 5.25 sq cm
There are two of these trapezoids that form the base faces of the trapezoidal prism. So the total base area is 2*5.25 = 10.5 sq cm
Keep this value (10.5) in mind. We'll use it later.
------------
Now onto the lateral surface area (LSA)
It turns out that the formula for the LSA is
LSA = p*d
where
p = perimeter of the trapezoid shown
d = depth or height of the 3D trapezoid (I'm not using h as it was used earlier)
This formula works for any polygonal base. It doesn't have to be a trapezoid.
In this case the perimeter is,
p = 1.7+2+2.65+5
p = 11.35
So
LSA = p*d
LSA = 11.35*10
LSA = 113.5
Add this LSA to the base area found earlier
10.5+113.5 = 124
The total surface area is 124 square cm
First make a guest check
My Guest check #9
1 donut = $1.29
Donut holes = $4.89
Dozen Donuts = $12
Donut Holes = $4.89
$1.29 + $4.89 + $12 + $4.89 = $23.07
$23.07 * 8% =<em> $24.92 is the 9th check list</em>
My Guest check #10
1 donut = $1.29
1 donut = $1.29
Dozen Donuts = $12
Donut Holes = $4.89
$1.29 + $1.29 + $12 + $4.89 = $19.47
$19.47 * 8% = <em>$21.03 is the 10th check list</em>
Answer:
Rational
Step-by-step explanation:
Give brainliest or at least a thanks please!