2. Find the solution set of the inequality:

Solve the system by substitution Y= -7x + 6 Y = - 10x Plz help

snow_tiger [21]

Answer:

(-2, 20)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = -7x + 6

y = -10x

Step 2: Solve for x

Substitution

Substitute in y [1st Equation]: -10x = -7x + 6
[Addition Property of Equality] Add 7x on both sides: -3x = 6
[Division Property of Equality] Divide -3 on both sides: x = -2

Step 3: Solve for y

Substitute in x [2nd Equation]: y = -10(-2)
Multiply: y = 20

7 0

3 years ago

Read 2 more answers

1. SPORTS Hector wants to buy a new football. He initially thought it would cost $36, but when he went to the sporting goods sto

Talja [164]

Answer:

It cost Hector $28.8

Step-by-step explanation:

How to find the answer:

36 - 20%

= $28.8

3 0

2 years ago

The dot plot below shows the number of cakes 31 chefs made in a week: Dot plot labeled Number of Cakes Made shows 4 dots over 1,

Paraphin [41]

The median, because the data is not symmetric and there are outliers is the data is not symmetric and there are outliers.

The median of the data set is 8 cakes, while the average is 7.5.

However, 21 of the 31 chefs, or roughly 2/3, made 8 or more cakes. This makes the median a better center for this data, since the data is clearly skewed. The four chefs that made 1 cake each brings the average down, skewing the mean and making the median a better representation of the data.

8 0

3 years ago

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The figure shows a circle inscribed in a triangle. To construct the inscribed circle, angle bisectors were first constructed at

klemol [59]

Answer:

Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

The above choice represents a bit of excess work. Actually, only one such perpendicular line segment needs to be constructed in order to determine the radius of the inscribed circle.

Once you know the center and radius, you can construct the inscribed circle.

7 0

3 years ago

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The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

3 years ago