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jeka94
3 years ago
15

2. Find the solution set of the inequality:

Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

I got a giid grade

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What is the decimal expression of the fraction 1/20?
kykrilka [37]
I think it is .05 but I am not 100% sure
4 0
3 years ago
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2x^3+2x^2-19x+20=0 find the roots of the polynomial equation
Alenkinab [10]
The answer is   x=-4, (3<span>±i)/2</span>
5 0
3 years ago
Find the area of the region under the graph of the function f on the interval
vlada-n [284]

Answer:

9/2

Step-by-step explanation:

this is a simple integral function

given limits of interval [a,b] of a continuous function f(t), you can find the area under the curve by using:

\int\limits^a_b {f(t)} \, dt

\int\limits^3_0 {3x-x^2} \, dx

using the fundamental theorem of calculus that states the integral of f(x) in the interval [a,b] is  = g(a)-g(b), where g(x) is the antiderivative of f(x)

our g(x) = \frac32x^2-\frac13x^3

g(3)-g(0) = g(3) = 27/2 - 27/3 = 27/2-9 = 9/2

8 0
3 years ago
Combine like term <br><br> 2a - 6 + 6 =
Murrr4er [49]

Answer:

2a

Step-by-step explanation:

-6 and +6 cancel out leaving the 2a by itself.

5 0
2 years ago
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If a rectangle is altered by increasing its length by 20 percent and its width by 10 percent, its area increases by a percent. W
aleksklad [387]

Answer:

D

Step-by-step explanation:

Remember that the formula for the area of a rectangle is:

A=lw

Where l is the our length and w is our width.

If we increase our length by 20%, this means that we add 20% or 0.2 of our old length to our old length. So, our new length will be:

l_{new}=l+.2l

Combine like terms:

l_{new}=1.2l

Similarly, if we increase our width by 10%, this means that we add 10% or 0.1 of our old width to our old width. So, our new width is:

w_{new}=0.1w+w

Combine like terms:

w_{new}=1.1w

Therefore, our new area will be:

A_{new}=(l_{new})(w_{new})

Substitute 1.2l and 1.1w. This yields:

A_{new}=1.2l(1.1w)

Multiply:

A_{new}=1.32lw

Our old area is:

A_{old}=lw

So, our area increased by a factor of 1.32.

This is the same as 32% of our old area.

So, our answer is D.

And we're done!

5 0
3 years ago
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