Question

An office has 30 computers. Seventeen of the 30 are Macintosh, and the remaining thirteen are windows. Two computers are randomly selected without replacement. What is the probability that the sample contains exactly one windows machine and exactly one Macintosh? If needed, round to FOUR decimal places. Pr(One Widows and One Macintosh) = ___________

Answer 1

Answer:

0.5085

Step-by-step explanation:

Given that an office has 30 computers. Seventeen of the 30 are Macintosh, and the remaining thirteen are windows.

When two computers are randomly selected without replacement

no of ways of selection = $60C2 = 1770$

No of ways of selecting one window and one Mac = $30C1(30C1) = 900$

Prob that the sample contains exactly one windows machine and exactly one Macintosh=$\frac{900}{1770} =0.5085$