Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Answer:
Option (3)
Step-by-step explanation:
From the figure attached,
AB and CD are two chords intersecting at O.
m∠AOD = 37°
m∠AOC + m∠AOD = 180° [Since these angles are supplementary angles]
m∠AOC = 180° - 37°
= 143°
By the theorem of intersecting chords,
Measure of angle formed is the half of the sum of measures of the arcs intercepted by the angle and vertical angle.
m∠AOC = 
143° = ![\frac{1}{2}[(x+5)+(x-5)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28x%2B5%29%2B%28x-5%29%5D)
143° = x
Therefore, Option (3) will be the answer.
(0,6) is on the y-axis. (5,-2) is on the 4th quadrant. (-1,10) is on the 2nd quadrant. (-1/4, -6*1/2) is on the 3rd quadrant. (5,0) is on the x axis. (8.7,2.3) is on the 1rst quadrant
Answer: jibjabjobjab it’s there
Step-by-step explanation:
Answer:
where is the figure to denote angles??