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Aneli [31]
3 years ago
10

Please answer this!!!!!!

Mathematics
1 answer:
aniked [119]3 years ago
5 0

To have a Proportionality equal to 1, you must have the same number in the numerator and denominator.

(D) y = x is your answer, because:

if y = 1, then x = 1, because of transitive property. And 1/1 = 1

if y = 2, then x = 2, because of transitive property. And 2/2 = 1

hope this helps

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Out of 3000 students in a School of Public Health, 1500 students defined themselves regular dietary supplement users. If you tak
attashe74 [19]

Answer:

The standard error of the proportion is 0.112.

Step-by-step explanation:

The standard error of a proportion is given by the following formula:

S = \sqrt{\frac{p(1-p)}{n}}

In which p is the probability of a success and n is the length of the sample.

In this problem

A success is a student defining themselves regular dietary supplement users. Our of 3000 students, 1500 do. So p = \frac{1500}{3000} = 0.5.

We take a sample of 20 of them, so n = 20.

So

S = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{20}} = 0.112

8 0
3 years ago
Gayle is making gift bags and must tie 250 ribbons to them. If Gayle can tie 4 ribbons every 10 minutes, how long will it take G
mart [117]

Answer:

625 minutes

Step-by-step explanation:

Given that:

Time taken to tie 4 ribbons = 10 minutes

Number of ribbons to be tied = 250

To find:

Time taken to tie 250 ribbons.

Solution:

First of all, we need to find the time taken to tie one ribbon.

And then we can multiply it with 250 to find the time taken to tie all the 250 ribbons.

For finding the time to tie one ribbon, we need to divide the time taken to tie 4 ribbons with 4.

Time taken to tie 1 ribbon = \frac{10}{4} = 2.5 minutes

Time taken to tie 250 ribbons = 2.5 \times 250 = <em>625 minutes</em>

4 0
2 years ago
Jenna and todd are running for president of a school club. The candidates for vice president are todd,annie, and luis. Because t
almond37 [142]

Answer:

B. P VP Jenna Todd Jenna Annie Jenna Luis Todd Luis Todd Annie

Step-by-step explanation:

CHECK THE COMPLETE QUESTION AND OPTIONS BELOW;

Jenna and Todd are running for president of a school club. The candidates for vice president are Todd, Annie, and Luis. Because Todd is running for both positions, he can't be elected vice president if he is elected president. Which list shows all the possible outcomes for president (P) and vice president (VP)? Answer options with 4 options A. P VP Jenna Annie Jenna Luis Todd Annie Todd Luis C. P VP Jenna Todd Jenna Annie Jenna Luis B. P VP Jenna Todd Jenna Annie Jenna Luis Todd Annie Todd Luis D. P VP Jenna Annie Jenna Luis Todd Jenna Todd Annie Todd Luis

From the question, Candidates that are running to be a president are;(Jenna and Todd)

Candidates that are running to become vice president are; (Todd, Annie, and Luis)

✓ Todd can only be elected as president or as vice president, if he is elected as president then he cannot be elected as vice president.

The list that shows all the possible outcome is

1)Vice president: Todd and President: Jenna

2)Vice president: Annie and President: Jenna

3)Vice president: Luiz and President: Jenna

4)Vice president: Annie and President: Todd

5)Vice president: Luiz and President: Todd

Hence, option B gives the correct answer.

5 0
3 years ago
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
The perimeter of the triangular park shown on the right is 14x-5. What is the missing​ length?
Lina20 [59]

Answer:70

Step-by-step explanation:

7 0
3 years ago
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