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3 years ago

What are some examples of axis of symmetry?

Mathematics

2 answers:

gregori [183]3 years ago

7 0

In a graph the axis of symmetry goes throught the lowest or highest point of it . The axis of symmetry is the same as the x value of the vertex .

kramer3 years ago

6 0

The axis of symmetry is the line of symmetry of a parabola; it divides into two equal halves that are reflections of each other.

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Which of the following options best describes the function graphed below?

hodyreva [135]

C.
The graph looks like it’s linear and is trending in an increasing way.

6 0

2 years ago

Mai will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $59.96 and costs an a

juin [17]

Answer:

600 miles.

Step-by-step explanation:

So basically we can write both plans as linear functions:

F(x) = $59.96+$0.14 . x

S(x) = $71.96+$0.12 . x

Where F(x) is the first plan, S(x) is the second one and X are the miles driven.

To know how many miles does Mai need to drive for the two plans to cost the same, we equalize both equations and isolate x.

F(x) = S (x)

$$59.96+$0.14.x = $71.96+$0.12.x \\0.14x-0.12x=71.96-59.96\\0.02x=12\\x=12 : 0.02\\x= 600$

Mai has to drive 600 miles for the two plans to cost the same-

4 0

3 years ago

Which angles are adjacent angles to 3? Select all that apply

sattari [20]

Two Answers: Angle 1, Angle 4

Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.

3 0

3 years ago

In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d

muminat

It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76°

3 0

3 years ago

Consider a triangle ABC like the one below. Suppose that a = 31, b = 23, and c = 20. (The figure is not drawn to scale.) Solve t

krok68 [10]

The solution to the triangle is A = 92.0, B = 47.9 and C = 40.1

<h3>How to solve the triangle?</h3>

The figure is not given;

However, the question can still be solved without it

The given parameters are:

a = 31, b = 23, and c = 20

Calculate angle A using the following law of cosine

a² = b² + c² - 2bc * cos(A)

So, we have:

31² = 23² + 20² - 2 * 23 * 20 * cos(A)

Evaluate

961 = 929 - 920 * cos(A)

Subtract 929 from both sides

32 =- 920 * cos(A)

Divide both sides by -920

cos(A) = -0.0348

Take the arc cos of both sides

A = 92.0

Calculate angle B using the following law of sine

a/sin(A) = b/sin(B)

So, we have:

31/sin(92) = 23/sin(B)

This gives

31.0189 = 23/sin(B)

Rewrite as:

sin(B) =23/31.0189

Evaluate

sin(B) =0.7415

Take arc sin of both sides

B = 47.9

Calculate angle C using:

C = 180 - 92.0 - 47.9

Evaluate

C = 40.1

Hence, the solution to the triangle is A = 92.0, B = 47.9 and C = 40.1