Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

Possible if they dont have to pay on the same months
Answer:
(-∞,7) U (7,∞)
Step-by-step explanation:
All real values of x such x ≠ 7
Answer
75r^4 t^2 + 25r^4 t^6
3/5x + 22 = 28
-22. -22
3/5x = 6
(5/3)(3/5)x = 6 × (5/3) multiply by the reciprocal
x = 6 × (5/3) -------------> 6 and 3 can be simplify so it will be x = 2 × 5 = 10
check
3/5 (10) + 22 ---> 3 × 2 + 22
28 = 28 ✔