Answer: Country A - 10machines
Country A - 1,000machines
Country A - 10,000machine
step-by-step explanation:
Since 10℅ of all machines becomes worthless every year, let's look at each country.
If 100 machines are all the machines in country A, then 10% of all the machines in country A (i.e 100 machines) will be 10% of 100 = 10 machines.
Similarly for country B, it will be equivalent to 10% of 10000, which is equal to 1,000machines.
Same goes for country C i.e 10% of 1000000 = 10,000machines are worthless.
Answer:
9.99 years
Step-by-step explanation:
P=$3,500
r=7%=0.07
n=4(quarterly)
A= double of $3,500=
$3,500×2=$7,000
t=?
A=p(1+r/n)^nt
$7,000=$3,500(1+0.07/4)^4t
$7,000=$3,500(1+0.0175)^4t
$7,000=$3,500(1.0175)^4t
Divide both sides by $3,500
2=(1.0175)^4t
Take the log to base 10 of both sides
log2=4t × log1.0175
0.30103=4t × 0.00753
0.30103=4(0.00753)t
0.30103=0.03012t
t=0.30103/0.03012
t=9.99435
Approximately
9.99 years
1) given x^4 + 95x^2 - 500
2) split in two factors with common factor term x^2: (x^2 + )(x^2 - )
3) find two numbers that add up 95 and their product is - 500:
=> 100*(-5) = - 500 and 100 - 5 = 95
=> (x^2 + 100)(x^2 - 5)
4) factor x^2 - 5 = (x + √5) (x - √5)
5) write the prime factors: (x^2 + 100) (x + √5) (x -√5)
6) find the solutions:
x^2 + 100 = 0 => not possible
x + √5 = 0 => x = - √5
x - √5 = 0 => x = √5
Answer: x = √5 and x = - √5
Answer: you already gave the answer. To check it submit
factor 3x^4y^3 − 15x^2y^2 + 6xy
to Wolfram Alpha.
3xy(x^3y^2 − 5xy + 2) is the "irreducible factorization".
