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Verizon [17]
3 years ago
9

(11-6)^2+6x2-(3+3)^2 A. 0 B. 1 C. 16 D. 26

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0

Answer: =1

Step-by-step explanation:

\left(11-6\right)^2+6\cdot \:2-\left(3+3\right)^2

=5^2+6\cdot \:2-\left(3+3\right)^2

=5^2+6\cdot \:2-6^2

=25+6\cdot \:2-6^2

=25+6\cdot \:2-36

=25+12-36

=1

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3 years ago
Integration of (3X(X^2+3)^4) dx<br><img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" " align="absmiddle" c
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Answer:


Step-by-step explanation:

\int 3x(x^2+3)^4 \ dx.

It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.

Integration by substitution involves swapping the variable x for another variable which depends on x: u(x). (We are going to choose u for this question).

The very first step is to choose a suitable substitution. That is, an equation u=f(x) which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution u=\text{The Term}.

Your integral contains the term x^2 + 3. The derivative is 2x and (ignoring the constants) we see x is also in the integral and so the substitution u=x^2+3 will unravel this integral!

Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").

u=x^2+3 \Rightarrow \frac{du}{dx}=2x \Rightarrow dx = \frac{1}{2x} du

Then,

\int 3x(x^2+3)^4 \ dx = \int 3x \cdot u^4 \cdot \frac{1}{2x} du = \int \frac{3}{2}u^4\ du.

The substitution has made this integral is easy to solve!

\int \frac{3}{2}u^4\ du= \frac{3}{10}u^5 + C

Finally we can substitute back to get the answer in terms of x:

\int 3x(x^2+3)^4 \ dx = \frac{3}{10}(x^2+3)^5+C

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Step-by-step explanation:

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