Question

(11-6)^2+6x2-(3+3)^2 A. 0 B. 1 C. 16 D. 26

Answer 1

Answer: =1

Step-by-step explanation:

$\left(11-6\right)^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-6^2$

$=25+6\cdot \:2-6^2$

$=25+6\cdot \:2-36$

$=25+12-36$

$=1$