The value of the P(A∩B) is equal to 0.04.
We have given that,
P(A)= 0.4 and P(B) = 0.85.
We have to determine the P(A and B)
<h3>What is the formula for Independent Events?</h3>
For Independent Events,
P(A) × P(B) = P(A∩B)
so we have, P(A∩B) = 0.4×0.1
P(A∩B) = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04
P(A'∪B) = 0.64
To learn more about the events visit:
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857 x 132= 113,124
work is showed in the image
Answer:
B and D
Step-by-step explanation:
they're the explanations.
Hi there!
"mph" stands for "miles per hour".
This means that the car travels 55 miles in 1 hour.
To find your answer, you'll need to use the cross product method :
55 miles → 1 hour
206.35 → x
(1 × 206.35) ÷ 55 = x
206.35 ÷ 55 = x
206.35 ÷ 55 = 3.751818...
206.35 ÷ 55 ≈ 3.75
0.75 × 60 = 45 minutes
Your answer is: It takes 3 hours and 45 minutes for the car to arrive at its destination.
There you go! I really hope this helped, if there's anything just let me know! :)
Answer: 63lbs
Step-by-step explanation:
The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs
This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).
To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.
Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.
Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.
