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2 years ago

A container shaped as a rectangular prism can hold 840 wooden cube blocks with edge lengths of

Mathematics

2 answers:

12345 [234]2 years ago

5 0

Answer:

105 ft^3

Step-by-step explanation:

I took my test on K12 and got 100% so everything was right, have a good day!

asambeis [7]2 years ago

4 0

First, fidn the volume of the little cubes that the rectangular prism can hold instide of itself. The formula for volume is length x width x height. This means you have to multiply 1/2 x 1/2 x 1/2. 1/2 x 1/2 x 1/2 = 1/8. Now, since the rectangular prism can hold 840 of these cubes, you need to multiply each cube's volume, 1/8, by 840. 1/8 x 840 = 105.

Your answer should be: 105 ft.^3

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Let z = 17. What is the value of 51 – z?

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You replace z with 17
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3 years ago

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Which of the following products is negative? Select all that apply. *

AlekseyPX

Answer:

(-4)(9)
(6)(-6)

Step-by-step explanation:

$(-4)(-9)\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=4\times\:9\\= 36$

$(-4)(9)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-4\times\:9\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:9=36\\=-36$

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$(6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times \:6=36\\=-36$

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3 years ago

(2a²-a²-7a+2)÷(a-2) Answer Please

ikadub [295]

Answer:

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Step-by-step explanation:

I am assuming you mean

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1 year ago

Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month

dalvyx [7]

The IQR for the males' data is 25.
The difference between the median of the males' data and the female's data is 14.
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A reason for the outlier is that the number of dogs needing care increased.

<h3>What is the interquartile range?</h3>

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

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1 year ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

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If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

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$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

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$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

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$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

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$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

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1 year ago