The first incorrect is the second step so choice B. ,bc. the exponents need assuming not multiply
hope helped
Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:
![x_{vertex}= -b/2a](https://tex.z-dn.net/?f=x_%7Bvertex%7D%3D%20-b%2F2a)
Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:
![f(-13/4)= -9/8](https://tex.z-dn.net/?f=f%28-13%2F4%29%3D%20-9%2F8)
Then your expression for this quadratic should be:
![f(x)=2\,(x+\frac{13}{4} )^2+(-\frac{9}{8})](https://tex.z-dn.net/?f=f%28x%29%3D2%5C%2C%28x%2B%5Cfrac%7B13%7D%7B4%7D%20%29%5E2%2B%28-%5Cfrac%7B9%7D%7B8%7D%29)
Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one
the value of x is 8 cm.
<u>Step-by-step explanation:</u>
Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.
We have ,
the area of a circle = πr²
the outer circle area = ![\pi(2x)^2 =4\pi x^2](https://tex.z-dn.net/?f=%5Cpi%282x%29%5E2%20%3D4%5Cpi%20x%5E2)
the inside circle area = ![\pi (6)^2= 36\pi](https://tex.z-dn.net/?f=%5Cpi%20%286%29%5E2%3D%2036%5Cpi)
According to Question,
the outer circle area - the inside circle area = he shaded region
⇒ ![\pi (4x^2)-36\pi =220\pi](https://tex.z-dn.net/?f=%5Cpi%20%284x%5E2%29-36%5Cpi%20%3D220%5Cpi)
⇒ ![x^2-9 =55](https://tex.z-dn.net/?f=x%5E2-9%20%3D55)
⇒ ![x^2=64](https://tex.z-dn.net/?f=x%5E2%3D64)
⇒![x =\sqrt{64}=8](https://tex.z-dn.net/?f=x%20%3D%5Csqrt%7B64%7D%3D8)
Therefore , the value of x is 8 cm.
Answer:
y=34x−8
Step-by-step explanation:
Answer:
Inequality: x > -2
Interval Notation: ( -2, ∞)
Step-by-step explanation: