There are 3 3/4 cups of flour 1 1/2 cups of sugar 2/3 cups of brown sugar and 1/4 cups of oil in a cake mix how many cups of in
1 answer:
You might be interested in
Answer:
C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.
Step-by-step explanation:
The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.
- There is an n×n matrix C such that CA=
.
- There is an n×n matrix D such that AD=
- The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
- For each column vector b in
, the equation Ax=b has a unique solution.
- The columns of A span
Therefore the statement:
If there is an n X n matrix D such that AD=I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:
- The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
The correct option is C.
Answer:
a) 0.0256 = 2.56% probability of 4 heads.
0.1296 = 12.96% probability of 4 tails.
b) The probability is 0.0576 = 5.76%.
c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses
Step-by-step explanation:
For each throw, we have these following probabilities:
0.4 = 40% probability of heads.
0.6 = 60% probability of tails.
(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.
4 heads:
4 throws, each with 0.4 probability of heads. So
0.0256 = 2.56% probability of 4 heads.
4 tails:
4 throws, each with 0.6 probability of tails. So
0.1296 = 12.96% probability of 4 tails.
(b) Determine the probability of H T H T in 4 tosses.
H = 0.4, T = 0.6. So
The probability is 0.0576 = 5.76%.
(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)
Number of outcomes:
The possible outcomes are:
H - H - T - T
H - T - H - T
H - T - T - H
T - H - H - T
T - H - T - H
T - T - H - H
6 outcomes given 2 heads in 4 tosses.
Each with probability 0.0576, as found in b)
6*0.0576 = 0.3456
0.3456 = 34.56% probability of 2 heads in 4 tosses