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2 years ago

Which number is represented by point E on the graph?

Mathematics

2 answers:

Fofino [41]2 years ago

4 0

-0.25 I fell that this is the answer because it is the only one that would make sense

Minchanka [31]2 years ago

4 0

Answer:-0.25

Step-by-step explanation:

idk

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Find the value or measure. Assume all lines that appear to be tangent are tangent. X=

aev [14]

According to the secant-tangent theorem, we have the following expression:

$(x+3)^2=10.8(19.2+10.8)$

Now, we solve for <em>x</em>.

$\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}$

Then, we use the quadratic formula:

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where a = 1, b = 6, and c = -315.

$\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}$ <h2>Hence, the answer is 15 because lengths can't be negative.</h2>

7 0

1 year ago

In a class library, 3 out of 4 books are non-fiction. The rest are fiction. a) How many non-fiction books could there be? How ma

iVinArrow [24]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

There can be infinite solutions to this problem

Here are some examples

3 4

6 8

12 16

24 32

48 64

96 128

To get a solution, just multiply both numbers by the same term. I multiplied by 2 each.

Hope this helps :)

-jp524

6 0

2 years ago

A triangle has an area of 14 square units. Its height is 7 units. What is the length of its base?

navik [9.2K]

The base should be 4.
Area=1/2* b *h
4*7=28/2=14.

3 0

3 years ago

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0

3 years ago

What does the line 4x -3y = 7 look like?

AlexFokin [52]

C) tilted right upward

3 0

3 years ago

Read 2 more answers