Could you please send a picture of the polygon?
I believe the answer is 1/3
You can solve this in two ways.
1. Graphical. Plot the graph for x between -5 and 1 (see attachement).
The vertex of the graph is the peak of the curve, which has the coordinates x=-2, y=-9.
2. Analytical. Calculate the derivative of the function f(x)

Solve the equation:

will give the solution x=-2.
Replace x=-2 in the f(x) function and you'll get the value of y:

You get the same answer: x=-2, y=-9
So the answer is
<span>B. (-2, -9)</span>
If the ratio of red marbles to blue marbles in a jar is 3 to 8, the meaning is for every 3 red marbles there are 8 blue marbles.
3 red marbles------------------8 blue marbles.
ratio=3/8
we have 40 blue marbles; we have to compute the number of red marbles.
1) Method 1; by the rule three.
3 red marbles-----------------8 blue marbles
x----------------------------------40 blue marbles
x=(3 red marbles * 40 blue marbles) / 8 blue marbles=15 red marbles.
answer: B. 15
Method 2: the ratio of red marbles to blue marbles is
ratio=number of red marbles / number of blue marbles
ratio=3/8
if we want to compute the number of red marbles we have to multiply the number of blue marbles by this ratio.
number of red marbles=ratio (red/blue)* number of blue marbles
number of red marbles=(3/8)*40=15
Answer: B.15
Any integer's sum and the reverse is equal to zero. You can add two positive integers the result will always be a positive sum, including two negative whole numbers dependable yields a negative aggregate. To discover the whole of a positive and a negative number, take the outright estimation of every number and after that subtract these qualities.