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4 years ago

HELP PLEASEE ASAP

2 answers:

5 0

The correct statement is the initial value represents the 2 gigabytes of data stored on the computer when Jackie bought it, and the rate of change represents the 3.5 gigabytes per year that Jackie is storing

Kryger [21]4 years ago

5 0

Think about what it means in the context of this problem for time to be equal to zero; it means that <em />the computer <em>already had 2 gigabytes on it the moment Jackie bought it</em>. That means that the 2 GB value at time = 0 must be the 2 GB already on the computer. Right away, you can eliminate three of the answers that don't contain that detail, finding that the correct response is the first one. The second half of that statement also aligns with the information we were given in the problem about the 3.5 GB/yr storage rate.

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Please help!<br> 5+4(2a+3) ≤-3(a+1)+31

Alborosie

Answer:

20a (less than or equal to) 28a

Step-by-step explanation:

PEMDAS

2a + 3= 5a

4*5a=20a

2. a+1=1a

-3*1a=-3a

-3a+31= 28a

3 0

4 years ago

How can I get someone to stop holding a grudge and mocking me at practice. I would really appreciate the help.

Nana76 [90]

Answer: Well first find out why that person is mocking you or holds a grudge against you. Try talking to that person. If that doesn't work, get a friend to help. To be honest, you can also always just ignore that person, there are many mean people out there.

Step-by-step explanation:

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3 years ago

What dose each mean in a math problem

Juli2301 [7.4K]

Answer:

Multiply

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is a rational number between 6.2 and 6.3

Nikitich [7]

.1 is the rational number

3 0

3 years ago

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago