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Answer:
Step-by-step explanation:
to solve this problem we can use the Pythagorean theorem
UT and TL are the legs, while LU is the hypotenuse
We have to find LU so we can proceed like this
x^2 + (x+1)^2 = LU^2
x^2 + x^2 + 1 + 2x = LU^2
2x^2 + 2x + 1 = LU^2
LU = +/- 
we have to take only the positive value because a length can’t be negative.
2x^2 + 2x + 1 is positive for every value of x, so the final answer is

Step-by-step explanation:
In order to find the number of solutions, we have to expand both sides out first.

First, expand 3(x-2), which will obtain 3x-6.
Next, expand (1/2)(6x-2), which gives 3x - 1.
The result at this point should be as shown below:

Now, we would shift all x terms to the left and all number terms to the right.

After simplifying, the final equation would be:

This is a linear equation and it has one solution.

Y=58
Y+14/6=12
Cross multiply to solve
So y+14=72 then subtract 14 so
Y=58