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Mashcka [7]
3 years ago
7

What is the answer to #14 and how did you do itthank you

Mathematics
2 answers:
Nostrana [21]3 years ago
8 0
I think to find the 50th term replace 50 for x and solve
Greeley [361]3 years ago
7 0
The problem actually starts at number 13! Because the answer is partially correct.

The explicit function for the sequence shown is actually y=-10 + -10(n-1)

The way to test out if that is the correct function is by testing if the first number is actually -10.

y= -10 + -10(1-1)
(Note: you plug in 1 into because we're testing the FIRST Number of the sequence.)
y= -10 - 10(0)
y= -10

It tested correct! Now let's make sure with the fourth sequence to ensure the function is correct. We'll do this by plugging in 4, and making sure we get -40.

y= -10-10(4-1)
y= -10-10(3)
y= -10-30
y=-40

Okay! So our function is correct. Now, we find the 50th number by plugging in 50.

y= -10-10(50-1)
y= -10- 10(50)
y= -10- 500
y= -510

So the answer to number 14 is -510! 

Hope this helps. xx
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In a map scale of 2.5 cm : 400 m, the distance between the supermarket and the gas station is 5.5 cm. Work out the real distance
Marianna [84]

Answer:

880m

Step-by-step explanation:

2.5cm = 400m

1cm = 400/2.5

=160m

5.5cm = 160 × 5.5

=880m

7 0
3 years ago
WORTH 30 POINTS PLEASE HELP
Vlad1618 [11]
Group A:
1 dot at 9:     1 x    9 =     9
7 dots at 10: 7 x 10 =   70
8 dots at 15: 8 x 15 = 120
8 dots at 17: 8 x 17 = 136
6 dots at 19: 6 x 19 = 114

Mean: (9+70+120+136+114) / (1+7+8+8+6) = 449/30 = 14.97

Group B:
6 dots at 10: 6 x 10 = 60
5 dots at 14: 5 x 14 = 70
6 dots at 18: 6 x 18 = 108
5 dots at 25: 5 x 25 = 125
4 dots at 28: 4 x 28 = 112
4 dots at 29: 4 x 29 = 116

mean: (60+70+108+125+112+116) / (6+5+6+5+4+4) = 591 / 30 = 19.70

The group that has a lower mean age of painting students is Group A. Its mean is 14.97 or 15 years of age.
8 0
3 years ago
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Can someone pls help me
jolli1 [7]

Answer:

x=−8 and y=−4

Step-by-step explanation:

8x−17y=4;−8x+15y=4

add eqn1 and 2

to eliminate x

you will get y=-4

put it zin eqn 1

x=-8

8 0
3 years ago
Please help please please help
Lana71 [14]

Answer:

The correct answer is B. 3 ft, 6 ft, 5 ft

Step-by-step explanation:

A right triangle has side lengths that equal 90 degrees

3 x 6 x 5 = 90 ft.

6 0
3 years ago
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Each person in random samples of 207 male and 253 female working adults living in a certain town in Canada was asked how long, i
Sergeu [11.5K]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females (P-value=0.155).

Step-by-step explanation:

The data is:

Males n1=207 M1=31.6 s1=24.0

Females n2=253 M2=29.3 s2=24.3

This is a hypothesis test for the difference between populations means.

The claim is that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

Then, the null and alternative hypothesis are:

H_0: \mu_m-\mu_f=0\\\\H_a:\mu_m-\mu_f> 0

The significance level is 0.05.

The sample 1 (males), of size n1=207 has a mean of 31.6 and a standard deviation of 24.

The sample 2 (females), of size n2=253 has a mean of 29.3 and a standard deviation of 24.3.

The difference between sample means is Md=2.3.

M_d=M_m-M_f=31.6-29.3=2.3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{24^2}{207}+\dfrac{24.3^2}{253}}\\\\\\s_{M_d}=\sqrt{2.783+2.334}=\sqrt{5.117}=2.262

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_m-\mu_f)}{s_{M_d}}=\dfrac{2.3-0}{2.262}=\dfrac{2.3}{2.262}=1.017

The degrees of freedom for this test are:

df=n_1+n_2-1=207+253-2=458

This test is a right-tailed test, with 458 degrees of freedom and t=1.017, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.017)=0.155

As the P-value (0.155) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

7 0
3 years ago
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