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OLEGan [10]
3 years ago
5

(5g + 4) +3 (g - 1) what is the answer just for fun btw..

Mathematics
2 answers:
Artyom0805 [142]3 years ago
8 0
8g+1 just worked it out
ExtremeBDS [4]3 years ago
6 0

Answer: 8g + 1

Step-by-step explanation:

(5g + 4) + 3(g - 1)

5g + 4 + 3g - 3

Bring like terms together

5g + 3g + 4 - 3

Combine like terms

8g + 1

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Evaluate 2*((4^2)^-1)
olga_2 [115]
4^2 = 16
16^-1 = .0625
2(.0625) = .125
5 0
2 years ago
Find SY and XY. PLEASE HELP ME IT IS DUE SOON IF YOU DONT KNOW DO NOT ANSWER
alina1380 [7]

Answer:

SY = 16

XY = 12

Step-by-step explanation:

15/20 = 12/SY

15SY = 240

SY = 16

15/20 = 9/XY

15XY = 180

XY = 12

5 0
3 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
Anastasia is grocery shopping with her father and wonders how much shopping is left to do. "We already have 6 0 % 60%60, percent
Molodets [167]
If there are 12 items adding up to 60%, we want to know how many items more it will take to equal 100% So set up this equation 12/x = .6 then solve for x. x=12/.6 x = 20 now that we know the total you can subtract 12 from 20 and get 8, that is the number of items left on the list.
8 0
3 years ago
Read 2 more answers
-2/x^2-4 + x-1/x^2-2x
Fiesta28 [93]

Answer:

I need help with this too

Step-by-step explanation:

8 0
3 years ago
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