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d1i1m1o1n [39]
4 years ago
10

Decide, without calculation, if each of the integrals below are positive, negative, or zero. Let D be the region inside the unit

circle centered at the origin. Let T, B, R, and L denote the regions enclosed by the top half, the bottom half, the right half, and the left half of unit circle, respectively.1. ∬B xe^xdA2. ∬R xe^xdA3. ∬T xe^xdA4. ∬D xe^xdA5. ∬L xe^xdA? Positive Negative Zero
Mathematics
1 answer:
Schach [20]4 years ago
4 0

The integrals over B and T will be positive. Keeping y fixed, xe^x is strictly increasing over D as x increases, so the integrals over x (i.e. the bottom/top left quadrants of D) is negative but the integrals over x>0 are *more* positive.

The integrals over R and L are zero. If we take f(x,y)=xe^x, then f(x,-y)=f(x,y), which is to say f is symmetric across the x-axis. For the same reason, the integral over all of D is also zero.

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Step-by-step explanation:

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3 years ago
A container is 1/8 full of water. After 10 cups of water are added,the container is 3/4 full. What is the volume of the containe
Liula [17]

<u>Answer</u>

16 cups

<u>Explanation</u>

First we find the difference between 1/8 and 3/4 of the container.

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= 5/8

From here we can say that;

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8 0
4 years ago
Read 2 more answers
Use the percent formula, A=PB: A is P percent of B, to solve the problem.
Reika [66]

Given parameters:

Percent formula;

               A  = PB

  P is the percentage

  B is the quantity

From the expression,

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   B = 600

Now input the known parameters and solve;

     A  = \frac{4}{100}  x 600

    A = 4 x 6  = 24

So, 4% of 600 is 24

5 0
4 years ago
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