1+3+5+7+...+999 =
= 1+2+3+4+...+500
+1+2+3+...+499
= 2·(1+2+3+...+499) + 500
= 2·(499·500)/2 + 500
= 499·500 + 500
= 500·(499 + 1)
= 500·500
= 250.000
Answer:
1,177.5
Step-by-step explanation:
I have not done this is a while but the formula is v = 3.14 r^2 h
so 3.14 x 5^2 x 15
then 3.14 x 25 x 15
lastly multiply it all to get 1,177.5
Hope this helps <3
Answer: The price for the computer = $1152
Step-by-step explanation:
Let the first boy = F
Let the second boy = S
Let the price of computer = C
The second boy had 5/ 6 of the money the first had. I.e
S = 5/6 F
Then F = 6/5S ......(1)
The first boy had 7 /8 of the price of the computer. That is
F = 7/8C ....... (2)
Substitute F in (1) into (2)
6/5S = 7/8C
S = 5/6 × 7/8C
S = 35/48C ......(3)
Together they had $696.00 more than they need to pay. That is
F + S = C + 696 ........ (4)
Substitute equation 2 and 3 into 4
7/8C + 35/48C = C + 696
0.875C + 0.729C = C + 696
0.604C = 696
C = 696/0.604
C = 1152 dollars
Therefore, the price for the computer = $1152
Answer:
1329.85≤μ≤1330.14
Step-by-step explanation:
z score for 99% confidence interval
from the z table we can find that the score for 99% confidence is 2.58
formula
z=![\frac{x-μ}{[tex]\frac{{σ}[tex]\sqrt{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-%CE%BC%7D%7B%5Btex%5D%5Cfrac%7B%7B%CF%83%7D%5Btex%5D%5Csqrt%7Bn%7D)
}[/tex]}[/tex]
where
x-sample mean
μ-population mean
σ-population standard deviation
n-sample size
2.58=![\frac{1330-μ}{[tex]\frac{{442}[tex]\sqrt{24}](https://tex.z-dn.net/?f=%5Cfrac%7B1330-%CE%BC%7D%7B%5Btex%5D%5Cfrac%7B%7B442%7D%5Btex%5D%5Csqrt%7B24%7D)
}[/tex]}[/tex]
1330-2.58×24÷442≤μ≤1330+2.58×24÷442
1329.85≤μ≤1330.14
<em><u>Answer:</u></em>
(7, -5)
<em><u>Step-by-step explanation:</u></em>
We can see the dot, is 7 units to the right of the y axis, and 5 down from the x-axis. We then can create the coordinates because we know where it is:
If it is on the right side of the y-axis, it is positive. If it is below the x-axis, it is negative so:
(7, -5) would be the coordinate point
