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kifflom [539]
3 years ago
11

if a Scientist records a jackrabbit traveling 140m in 7 s. At what do bead does the jackrabbit travel in meters per second​

Mathematics
1 answer:
viktelen [127]3 years ago
4 0
Meters PER second just means meters divided by seconds:
140/7 = 20 meters per second
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Need to find shaded area of figure please help!
devlian [24]

Answer:

39 ft^2

Step-by-step explanation:

Find the area of the triangle and subtract the area of the square.

area of triangle = bh/2

area of square = s^2

shaded area = bh/2 - s^2

shaded area = (20 ft)(16 ft)/2 - (11 ft)^2

shaded area = 160 ft^2 - 121 ft^2

shaded area = 39 ft^2

7 0
3 years ago
How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.
True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

  • if a > 0  (h', k) is a minimum point and
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Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

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So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

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4 0
2 years ago
A geometric sequence can be used to describe the population of rabbits on a
vlabodo [156]

Answer:

step 1

Find the average growth per year of the populations of rabbits farm A

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=40

average=[40-5]/2---------> 17.5

step 2

Find the average growth per year of the populations of rabbits farm B

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=30

average=[30-5]/2---------> 12.5

step 3

Compare the average growth per year of the populations of rabbits on both farms

farm A=17.5

farm B=12.5

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.

therefore

the answer is the option C)

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.

Step-by-step explanation:

6 0
2 years ago
Max points and brainliest
Paul [167]

Answer:

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Step-by-step explanation:

slope = (y1-y2)/(x1-x2)

= (3-1)/(0-1)

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= -2

3 0
4 years ago
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My number 4752512944
choli [55]

Answer:

no thanks for your number

Step-by-step explanation:

Have a great day

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