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2 years ago

if a Scientist records a jackrabbit traveling 140m in 7 s. At what do bead does the jackrabbit travel in meters per second

Mathematics

1 answer:

viktelen [127]2 years ago

4 0

Meters PER second just means meters divided by seconds:
140/7 = 20 meters per second

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2 years ago

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Point B is a point of tangency. Find the radius r of OC.<br> А 9<br> B<br> r<br> n

insens350 [35]

Answer:

Radius, r, is 3.75

Step-by-step explanation:

From the given diagram,

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Thus applying the Pythagoras theorem, we have;

$/AC/^{2}$ = $/AB/^{2}$ + $/BC/^{2}$

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2 years ago

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3 years ago

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3 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

if a Scientist records a jackrabbit traveling 140m in 7 s. At what do bead does the jackrabbit travel in meters per second​

if a Scientist records a jackrabbit traveling 140m in 7 s. At what do bead does the jackrabbit travel in meters per second